Thursday, February 21, 2013

Answer Pre Algebra Questions

Introduction to answer pre algebra questions:

Pre algebra is a method of calculating the number system by different methods like linear equations and geometry methods. In algebra each and every systems has a common formula to explain its all concepts.
Pre algebra is a easiest number system where we can implement the techniques for any algebra calculations.
Pre algebra describes about the fraction, decimals, polynomials, ratios, geometry, measurements and integers and other number formats.

Example for answer pre algebra questions :


1)  solve the question:   g + 79 = 194

Answer:

g + 79 = 194

g + 79 - 79 = 194 - 79 ( add -79 on both sides, we get)

g = 115.

2)    Solve:   n - 56 = 604

Answer:

n - 56 = 604

n - 56 + 56 = 604 + 56 ( add 56 on both sides,we get)

n = 660

3)    compute:   `m / 5` = 10

Answer:

`m / 5` = 10

5`(m / 5)` = 10(5) ( multiply by 5 on both sides, we get)

m = 50

4)    fine the value of s in the given question:   7s - 7 = 42

Answer:

7s - 7  = 42

7s - 7 + 7 = 42 + 7 (  add 7 on both sides, we get)

7s = 49

(7s) / 7 = 49 / 7 ( divide by 7 on both sides, we get)

s = 7

5)    find:   5(h + 2) = 25

Answer:

5(h + 2) = 25

[5(h + 2]/5 = 25/5 (divide by 5 on both sides, we get)

h + 2 = 5

h + 2 -2 = 5 -2 ( add -2 on both sides, we get)

h = 3

6)    The amount of twice a digit plus 13 is 75.  Find the number.

Answer:
Answer:

•    The word "is" represents equals.

•    The word "and" represents plus.

•    Therefore, we can rewrite the problem like the following:

•    The total of twice a number and 13 equals 75.

•     Using figures and a variable that denotes something, D in this case (for digit),

•    we can write an equation that represents the same thing as the given problem.

2D + 13 = 75

By solving this equation by isolating the variable.

2D + 13 = 75 Equation.

- 13 = -13 Add (-13) to both sides.

-------------------

2D = 62

D = 31 Divide 2 on both sides.

So the number is 31.


Answer pre algebra questions: Practice problems


1) (9n 2 + 15n + 9) + (14n 2 + 12n + 8) = ?

Answer: 23n 2 + 27n + 17  (after solving the question)

2) (2a + b) + ( –a + 4b) = ?

Answer: a + 5b ( after solving the question)

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