Long Math Problem

Introduction on long math problem

This article is about long math problem. Long math problem will contain a lot of step in solving the problem to obtain the final solution. In some of the long math problem we use different formula to obtain the solution. There are many long math problem in many different math chapters. Each topics of mathematics have different solving properties theorem methods and formulas. There are many websites and online tutors to help with long math problem. Many stiudents favorite and best website to solve long math problem is tutor vista. Below we can see one long math problem.

Long Math Problem

Long math problem does not means that the given problem must be long. It also means the steps taken to solve some problems lead to long math problem. Below we solved one math problem which have a long steps to obtain the entire solution.
1. Solve the equations: p + 2q + 3r = 14, 3p + q + 2r = 11, 2p + 3q + r = 11.

Solution: Let the given equations be identified as follows:

p + 2q + 3r = 14------- (1)

3p + q + 2r = 11------ (2)

2p + 3q + r = 11------ (3)

Consider the equations (1) and (3)

(1) ? p + 2q + 3r = 14

(3) × 3 ? 6p + 9q + 3r = 33 subtracting

–5p – 7q = –19

5p + 7q = 19 (4)

Consider the equations (2) and (3)

(2) ? 3p + q + 2r = 11

(3) × 2 ? 4p + 6q + 2r = 22 subtracting

–p – 5q = –11

p + 5q = 11 (5)

Consider the equations (4) and (5)

(4) ? 5p + 7q = 19

(5) × 5 ? 5p + 25q = 55 subtracting

–18q = –36; ?q = 2

Substitute q = 2 in (5) we get

p + 5(2) = 11; p + 10 = 11; ?p= 1

Substitute p = 1, q = 2 in (3) we get

2(1) + 3(2) + r = 11; 2 + 6 + r = 11 ? r = 3

The solution is p = 1, q = 2, r = 3.


Long Math Problem

Similar to the above problem there are more number of math problems to solve with long steps. In some problems the given math problem will be long and the solution will be a shorter one. In some cases the solution and the problem both will be a longer one. Here are some problem similar to the solved problem above for your practice. The solution also given below and you have to try the steps similar to the problem solved above.

1. Solve: 3x – 3y + 4z = 14; –9x – 6y + 2z = 1; 6x + 3y + z = 5

Answer: The solution is x = 1, y = –1, z = 2

2. Solve: a + b = 3, b + c = –5, c + a = 2.

Answer: The solution is a = 5, b = –2, c = –3.

Multiply Symbol

Introduction of multiply symbol:

Multiplication or Times is fundamental operation on whole numbers. The fundamental operations on whole numbers are addition, subtraction, multiplication, and division. The time is the process of repeated addition of a number. Times or multiply denoted by the symbol × or *. Elementary school students use the symbol × for multiplication (multiply) or times. Leibniz uses the cap symbol `nn`  for multiplication or times. This symbol is used to indicate intersection in set.

Multiplication Example

Multiplication or times indicates by placing the quantities to be multiplied side by side (juxtaposition). Multiplication or times is a short form of addition of the same number several times. The important of multiplication or times process is to place the digits value of the factors in the proper columns. That is, units number must be placed in the units column, tens in tens column, and hundreds in hundreds column. Notice that it is not essential to write the zero in the case of 15 tens (150) since the 1 and 5 are written in the proper columns.

Ex 1:   Multiply 283 by 101

Sol:    283 × 101 means 101 times 283

Or 100 times 283 + one time 283

Or 28300 + 283

Or 28583

Therefore 283 × 101 = 28583

Ex 2:  John earns four times, of what his brother earns. If his brother earns $1800 in a month, how much does John earn?

Sol :  John brother earn $1800

John earn three times more than his brother that is $1800 times 4 (Here the times indicate the symbol ×)

Therefore $1800 × 4

John earn $7200

Ex 3: Multiply 650 × 99

Sol :  650 × 99 means 99 times 650

Or 100 times 650 – one time 650 (Here the times indicate the symbol ×)

Or 65000 – 650

Or 64350

Therefore 650 × 99 = 64350

Practice Problem

1. Kim earns 5 times, of what his brother earns. If his brother earns $1500 in a month, how much does Kim earn?

Ans :  $7500

2. Multiply 350 × 470

Ans : 164500

3. In a town have four post offices. In each post office there are six workers. How many workers do the post offices have in total?

Ans : 24

4. Four children are playing cricket. They all brought 7 balls. How many balls do they have totaled?

Ans : 28

Ones Tenths Hundredths

Introduction to Ones Tenth Hundredths:

These ones, tenths and hundredths are representing the place value of the number. The number which has place value of ones is the number less than ten. That is the number in place value of ones  starts from 0 to 9. The number which has the place value of tenths is that number multiplied by `(1)/(10)` . The number which has the place value of hundredths is that number multiplied by `(1)/(100)` .

Ones Tenths Hundredths:

The standard form of place value exists in decimal number and fraction form. Generally in decimal number, digit place before the decimal point is called as ones and digit after the decimal point is called as tenths and digit after the tenths place is called as hundredths.

Example: x.yz, here

x is the digit placed before the decimal point – Ones.

y is the digit placed after the decimal point – Tenths = x *`(1)/(10)`

z is the digit placed after the tenths place – Hundredths = y * `(1)/(100)`

Example Problem – Ones Tenth Hundred:

Example 1:

Write the place value of ones in following numbers.

a)      2.9

b)      1123

c)      0.01

Solution:

a) 2.9

Given the number is the decimal number, and the digit before the decimal point is 2.

2 is the number having ones Place.

Answer: 2

b) 1123

Here the given number is not the decimal number, it is the whole number.

Step 1: Make the whole number as decimal number without changing the value as 1123.0

Now the ones place of the number 1123 is 3

Answer: 3

c) 0.01

Given the number is the decimal number, and the digit before the decimal point is 0.

0 is the number having ones Place.

Answer: 0

Example 2:

Say the ones tenth and hundredths of the following numbers.

a)      2.34

b)      17.456

Solution:

a) 2.34

The digit before the decimal point = 2 = Ones

The digit after the decimal point = 3 = tenths

The digit after the tenths place = 4 = hundredths.

b) 17.456

The digit before the decimal point = 7 = Ones

The digit after the decimal point = 4 = tenths

The digit after the tenths place = 5 = hundredths.

Tangent Line Formula

Introduction To Tangent Line Formula:

Normally Tangent Line is defined as the line which locally just touches a curve particularly at one and only one point .Specifically We have to know that there is no intersection at all in any other points in a curve.Tangent Line Formula is used to represnt the tangent line in an efficient manner.In this article we will see about the tangent line formula with some practice example problems.

Tangent Line Formula:
The tangent line  to a curve at a given point is the straight line that just touches the curve particular point. The point of tangency means that the tangent line is going in the same direction with the curve, and  it is the best straight-line approximation to the curve at that point.

Normally To find the formula for the Tangent line to the curve y=f(x) at point `p(x_o,f(x_0))` ,We need to find out the slope of the curve . Slope of the curve is also called as the gradient of the curve.

Slope of the curve  calculated by using the following two steps:

1.First we need to take the derivative of the curve equation,

`dy/dx=f'(x)`

2. Then evaluate the above equation at the point p(x_o,f(x_0))

`dy/dx=f'(x_0)=slope`

The Equation for the line if we are knowing the slope and point

`y-y_1=m(x-x_1)`

Here the points are`(x_0,f(x_0)` and slope is `f'(x_0)`

So the Tangent line formula is

`y-f(x_0)=f'(x_0)(x-x_0)`

Tangent Line Formula Example1:

Find the equation of the tangent line to the curve y = x4 at the point (2, 8).

Solution:

`dy/dx= 4x^2`

Slope of the Curve when  x = 2 is

4 × 22 = 16.
So apply the slope and points in the slope point formula of the line.

`y-y_1=m(x-x_1)`

`y - 8 = 16(x - 2)`

y = 16x – 24

This is the equation of the tangent line

Tangent Line Formula Example2:

Find the equation of the tangent line to the curve `y = 5x^3-4y^2`  at the point (1, 2).

Solution:

`dy/dx= 15x^2-8y`
Slope of the Curve  when the points are (1,2) is

`dy/dx=15-16`

`m =-1`

So apply the slope value and x and y values into the slope point formula of the line.

`y-y_1=m(x-x_1)`

` y - 2 = -1(x - 1)`

`y-2 = -x +1`

y+x=3

This is the equation of the tangent line

Define Loss Ratio

Introduction for define of loss ratio:

A relation is getting form the comparison of two quantities like in some wisdom is called a ratio. Ratio will be show by the terms of fraction, that is, a: b is equal to `a/b` for example 25 is `1/4` of the hundred; Therefore, the ratio of 25 to 100 is `1/4.` We can write it in ratio as 1:4. The loss ration is calculated as the total money paid out is divided by the sum of the money is taken for the premium is multiplied by the 100.

Loss ratio = `"total money paid out"/"sum of money taken for premium"` `xx` 100

Example for Define of Loss Ratio:

Example:

A company has paid out `$` 65000 in claims of a previous year to john. But the company has taken in a total of  `$` 100000 in premiums during a particular year. Calculate the loss ratio to define.

Solution:

Total money paid out = `$` 65000

Sum of money taken for premium = `$` 100000

Loss ratio = `"total money paid out"/"sum of money taken for premium"` `xx` 100

= `65000/100000` `xx` 100

= `65/100` `xx` 100

= .65 `xx` 100

= 65%

Therefore the loss ratio for the company is 65% .

Practice Problems for Definition of Loss Ratio:

Problem 1:

A company has paid out `$` 70000 in claims of a previous year to Martin. But the company has taken in a total of `$` 150000 in premiums during a particular year. Calculate the loss ratio to define.

Solution: The loss ratio for the company is 46.67%

Problem 2:

A company has paid out `$` 75000 in claims of a previous year to Paul. But the company has taken in a total of  `$` 200000 in premiums during a particular year. Calculate the loss ratio to define.

Solution: The loss ratio for the company is 37.5%

Problem 3:

A company has paid out `$` 80000 in claims of a previous year to Sarra. But the company has taken in a total of `$` 250000 in premiums during a particular year. Calculate the loss ratio to define.

Solution: The loss ratio for the company is 32%

Percent Word Problem Solving

Introduction to percent word problem solving:

In math, percent is an expression, expressing the fraction as a percent (that is "per" "cent" means "per" "hundred"). The percentage is represented as "%" sign. The percentage of the number is expressed as 7%. Percentage expresses whether one quantity is larger or smaller with respect to the other quantity. The word problem is expressed in which it fits the equation.

There are three steps to solving math word problems:

Translate into equations
Solve the equations and
Check the answer
In math percent word problems, we have to translate the simple English statements into mathematical expressions. For example “of” indicates multiplication (times). Percentage word problems can be easily solved by using the rule, If suppose,

"(x) is (some percentage) of (y)", which translates to "(x) = (some decimal) × (y)"



Formula for Percent Word Problem Solving:
Formula for percentage:

The formula for percentage is the following and it must be easy to use:

`"is"/"of" = "%"/"100"`

Example 1:

What percent of 40 is 50?

Solution:

The given statement is

Percent * 40 = 50

Therefore,

x % `xx` 40 = 50

`x/100` `xx` 40 = 50

`(40x)/100` = 50

Now cross multiply to get

40x = 50*100 = 5000

x = `5000/40`

x = 125

Therefore, Fifty is 125% of 40

Example 2:

25% of what is 30?

Solution:

The statement is

25% `xx` x = 30

Therefore,

`25/100` `xx` x = 30

`(25x)/100" ` = 30

x = `3000/25`

= 120

Answer: 30 is 25% of 120

Examples of Percent Word Problem Solving:

Example 3:

In a college, 30% of students are studying computer science. If their total number is 120, how many students are studying in that college totally?

Solution:

There are 30% of students are studing computer science. We understood that 30% of all students in college are equal to number of students studying computer science.

Therefore, the equation is

30% of x = 120

`30/100`` xx x` = 120

30 x = 120 * 100

30 x = 12000

x = 12000/30

x = 400

Therefore, we have 400 students in the college.

Practice Percentage Word Problems

Practice problem 1:

What percent of 15 is 20?

Answer key: 133.33

Practice problem 2:

40% of what is 70?

Answer key: 175

Practice problem 3:

In a test there are 30 questions in total. If john gets 70% correct, how many questions did john missed?

Answer key: John missed 9 questions

Equations with Variables on both Sides Calculator

Introduction for equations with variables on both sides calculator:

Equation with variable are the important part of algebra, generally the equation with same variable are said to be equation with  variables on both sides. Fro example x+2x+4 = x+8 here x is the variable in this equation we need to find the value of variable using calculator. In this article we will discuss about equation with variables on both sides calculator with suitable example problem.

Problem on Equations with Variables on both Sides Calculator:

Simplify the following equations with variables on both sides calculator

Problem(i) : The equation  is 2x+4 = 4x+6+8.

Solution

The given equation  is 2x+4 = 4x+6+8.

Step 1: In this given equation collect the variable

2x-4x+4 = 6+8

Step2: Collecting the constant

2x-4x+4 = 14

2x-4x = 14-4.

Step 3: simplifying the equation

-2x = 10

Step 4: Dividing both sides by -2

`(-2x)/-2` =`10/-2`

x= -5

Step 5: The variable of x is -5.

Problem(ii) : The equation  is 3x= 4x+6+1.

Solution

The given equation  is 3x = 4x+6+1.

Step 1: In this given equation collect the variable

3x-4x = 6+1

Step 2: Collecting the constant

3x-4x = 7

3x-4x = 7.

Step 3: simplifying the equation

-x = 7

Step 4: The variable of x is -7.

Problem on Equations with Variables on both Sides Calculator:

Simplify the following equations with variables on both sides calculator

Problem (i) The equation is -5x+7+8 = -9x +15+10

Solution

The given equation  is -5x+7+8 = -9x +15+10

Step 1: In this given equation collect the variable

-5x+9x+15 = 15+10

Step2: Collecting the constant

-5x+9x+15 = 25

-5x+9x = 25-15.

Step 3: simplifying the equation

4x = 10

Step 4: Dividing both sides by 4

`(4x)/4` = `10/4`

x = `5/2`

Step 5: The variable of x is `5/2` .

Problem (ii) The equation is -2x+7+13 = 4x +14

Solution

The given equation  is -2x+7+13 = 4x +14

Step 1: In this given equation collect the variable

-2x-4x+7+13 = 14

Step2: Collecting the constant

-2x-4x+20 = 14

-6x = 14-20

Step 3: simplifying the equation

-6x = -6

Step 4: Dividing both sides by -6

`(-6x)/-6` =`(-6)/(-6)`

x = 1

Step 5: The variable of x is 1.