Showing posts with label Trigonometry. Show all posts
Showing posts with label Trigonometry. Show all posts

Tuesday, November 20, 2012

Trigonometry Test Answers

Introduction to trigonometry test answers:

Trigonometry is an important branch of Mathematics. The word Trigonometry has been consequent from three Greek words Tri (Three), Goni (Angles), Metron (Measurement). Literally it means “measurement of triangles”. The fundamental trigonometric functions are Sine, Cosine and Tangent functions of a triangle takes an angle and give the sides of the triangle. The ordinary trigonometric terms are Sine, Cosine and Tangent.

Solving Trigonometric Functions on Trigonometry Test Answers:

Trigonometry test answers 1:

Solve the trigonometric equation.

(Find all solutions) 2 Cos x + 2 = 3

Solution:

First we have to solve for Cos x

2Cos x + 2 = 3

2Cos x =3 – 2

2Cos x = 1

Cos x = 1 / 2

X = Cos-1x (1/2)

X = 60

Trigonometry test answers 2:

Find the solutions for the trigonometric function:

-5 Cos 2x + 9 Sin x = -3

Solution:

-5 Cos2x + 9 Sin x = -3

-5(1- Sin2x) + 9Sinx = -3

-5 -5n2x + 9Sinx = -3

-5 -5Sin2x + 9Sinx +3 = 0

-5Sin2x + 9Sinx -2 = 0

Let us take y = Sin x

-5y2+ 9y – 2 = 0

Y = -2                                                     Y =-.2

Now plug y =sin x

Sin x = -2                                              Sin x = .2

X = Sin-1(-2)                                             X = Sin2(- .2)

X = - Sin-1(2)                                            X =-Sin-1(.2)

Trigonometry Test Answers 3 on Trigonometry Test Answers:

Prove (tanx+secx)/(cosx-tanx-secx)=-cscx

(tanx+secx) / (cosx-tanx-secx)
[(sinx+1)/cosx] / [(cos²(x)/cosx - sinx/cosx - 1/cosx]
[(sinx+1)/cosx] / [-(1-cos²x)/cosx - sinx/cosx]
[(sinx+1)/cosx] / [-sin²(x)/cosx - sinx/cosx]
[(sinx+1)/cosx] / [(-sin²(x)-sinx)/cosx]
[(sinx+1)/cosx]*[cosx/(-sin²(x)-sinx)]
(sinx+1)/-sin²(x)-sinx
sinx+1 / -sinx(sinx+1)
1/-sinx = -cscx

Trigonometry test answers 4:

Problem for trigonometric cosine function:

In a triangle adjacent side is 5 and hypotenuse is 25 then finds the angle A of the triangle?

Cos A= (adjacent) / (hypotenuse)

Cos A = 5/25

A = cos-1(5/25)

A = 78.46.

Trigonometry test answers 5:

Problem for trigonometric cosine function:

In a triangle adjacent side is 7 and hypotenuse is 2 then finds the angle A of the triangle?

Cos A= (adjacent) / (hypotenuse)

Cos A = 7/2

A = cos-1(7/2)

A = 0.998