Introduction to algebra ags answers:
Algebra ags answers deals with solving basic algebra problems whereas ags is the publication name in which one of the algebra problems with answers are published by ags. In ags, algebra is defined as the branch of mathematics which deals with finding unknowns with the help of known values. The ags algebraic problems with answers are discussed below. Alphabets are used for variable representation and numbers are considered as constants.
Algebra ags answers example problems:
Example 1:
Solve the ags algebraic expression.
-2(n - 1) - 4n - 1 = 3(n + 5) - 2n
Solution:
Given expression is
-2(n - 1) - 4n - 1 = 3(n + 5) - 2n
Multiplying the factor terms
-2n + 2 - 4n - 1 = 3n + 15 - 2n
Grouping the above terms
-6n + 1 = n + 15
Subtract 1 on both sides
-6n + 1 - 1 = n + 15 -1
Grouping the above terms
-6n = n + 14
Subtract n on both sides
-6n - n = n + 14 -n
Grouping the above terms
-7n = 14
Multiply by – `1/ 7` on both sides, we get
n = - `14/7`
N = 2
Conclusion:
n = 2 is the solution for the given expression.
Example 2:
Solve the ags algebraic expression.
-4(n + 2) = n + 12
Solution:
Given expression is
-4(n + 2) = n + 12
Multiply factors in left term
-4n - 8 = n + 12
Add 8 on both sides
-4n - 8 + 8 = n + 12 + 8
Grouping the above terms
-4n = n + 12
Subtract n on both sides
-4n - n = n + 20 -n
Grouping the above terms
-5n = 20
Multiply -`1/5 ` on both sides
n = -`20/5 `
N = -4
Conclusion:
n = - 4 is the solution for the given expression.
Algebra ags answers practice problems:
1) Solve the ags algebraic expression.
-3(n - 2) - 2n - 3 = 2(n + 5) - 4n
Answer: n = -`7/3` is the solution for the above given expression.
2) Solve the ags algebraic expression.
-2(n + 3) = 5n + 8
Answer: n = - 2 is the solution for the above given expression.
Algebra ags answers deals with solving basic algebra problems whereas ags is the publication name in which one of the algebra problems with answers are published by ags. In ags, algebra is defined as the branch of mathematics which deals with finding unknowns with the help of known values. The ags algebraic problems with answers are discussed below. Alphabets are used for variable representation and numbers are considered as constants.
Algebra ags answers example problems:
Example 1:
Solve the ags algebraic expression.
-2(n - 1) - 4n - 1 = 3(n + 5) - 2n
Solution:
Given expression is
-2(n - 1) - 4n - 1 = 3(n + 5) - 2n
Multiplying the factor terms
-2n + 2 - 4n - 1 = 3n + 15 - 2n
Grouping the above terms
-6n + 1 = n + 15
Subtract 1 on both sides
-6n + 1 - 1 = n + 15 -1
Grouping the above terms
-6n = n + 14
Subtract n on both sides
-6n - n = n + 14 -n
Grouping the above terms
-7n = 14
Multiply by – `1/ 7` on both sides, we get
n = - `14/7`
N = 2
Conclusion:
n = 2 is the solution for the given expression.
Example 2:
Solve the ags algebraic expression.
-4(n + 2) = n + 12
Solution:
Given expression is
-4(n + 2) = n + 12
Multiply factors in left term
-4n - 8 = n + 12
Add 8 on both sides
-4n - 8 + 8 = n + 12 + 8
Grouping the above terms
-4n = n + 12
Subtract n on both sides
-4n - n = n + 20 -n
Grouping the above terms
-5n = 20
Multiply -`1/5 ` on both sides
n = -`20/5 `
N = -4
Conclusion:
n = - 4 is the solution for the given expression.
Algebra ags answers practice problems:
1) Solve the ags algebraic expression.
-3(n - 2) - 2n - 3 = 2(n + 5) - 4n
Answer: n = -`7/3` is the solution for the above given expression.
2) Solve the ags algebraic expression.
-2(n + 3) = 5n + 8
Answer: n = - 2 is the solution for the above given expression.
